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Iron(II) Phosphate Percent Composition: A Detailed Guide

Iron(II) phosphate, also known as ferrous phosphate, is an inorganic compound with the chemical formula Fe₃(PO₄)₂. Understanding its percent composition is essential for chemical analysis, industrial applications, and academic research.

Chemical Formula and Molar Mass
The molar mass of iron(II) phosphate is calculated by summing the atomic masses of its constituent elements:
– Iron (Fe): 55.85 g/mol
– Phosphorus (P): 30.97 g/mol
– Oxygen (O): 16.00 g/mol

For Fe₃(PO₄)₂, the molar mass breakdown is:
– Fe₃: 3 × 55.85 = 167.55 g/mol
– (PO₄)₂: 2 × (30.97 + 4 × 16.00) = 189.94 g/mol
– Total Molar Mass: 167.55 + 189.94 = 357.49 g/mol

Percent Composition Calculation
The percent composition of each element in iron(II) phosphate is calculated as:

1. Iron (Fe):
\[
\text{\% Fe} = \left( \frac{167.55}{357.49} \right) \times 100 = 46.87\%
\]

2. Phosphorus (P):
\[
\text{\% P} = \left( \frac{2 \times 30.97}{357.49} \right) \times 100 = 17.33\%
\]

3. Oxygen (O):
\[
\text{\% O} = \left( \frac{8 \times 16.00}{357.49} \right) \times 100 = 35.80\%
\]

Applications of Iron(II) Phosphate
Iron(II) phosphate is widely used in:
– Fertilizers (as a slow-release phosphorus source)
– Lithium iron phosphate (LiFePO₄) batteries (due to its stability and safety)
– Corrosion inhibition in metal treatments

Conclusion
The percent composition of iron(II) phosphate (Fe₃(PO₄)₂) is approximately 46.87% Fe, 17.33% P, and 35.80% O. This breakdown is crucial for chemical synthesis, quality control, and industrial applications. Understanding these values ensures precise formulation in manufacturing and research.

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